Question

Possible Duplicate:
MySQL date format

i have this date which i need to make a comparison but i need to do it since the query!

Now i have this query:

Select date WHERE date="$today"

Where $todayis in this format :dmY
how can i directly transform it into dmY aswell? the date field?
Something like:

Select date("dmY",date) WHERE date="$today"

I don’t know if this is even possible to do, but i guess it might be, so i’d appreciate a little help even if it’s simply, yes, it’s doable, no, it’s not!

Answer 1

I think where you are having issues is formating the php date to fit with what is been formated from your mysql_query

Here’s what i came up with.

I have created a simple code for you to handle this.

The Procedure is that i got today’s date from mysql using CURDATE() function of mysql and then format it and match the exisiting column on the table

MYSQL DATABASE

    -- phpMyAdmin SQL Dump
-- version 3.4.5
-- http://www.phpmyadmin.net
--
-- Host: localhost
-- Generation Time: Oct 04, 2012 at 01:44 PM
-- Server version: 5.5.16
-- PHP Version: 5.3.8

SET SQL_MODE="NO_AUTO_VALUE_ON_ZERO";
SET time_zone = "+00:00";

--
-- Database: `my_db`
--

-- --------------------------------------------------------

--
-- Table structure for table `datetable`
--

CREATE TABLE IF NOT EXISTS `datetable` (
  `dateid` int(2) NOT NULL AUTO_INCREMENT,
  `datestuff` date NOT NULL,
  PRIMARY KEY (`dateid`)
) ENGINE=MyISAM  DEFAULT CHARSET=latin1 AUTO_INCREMENT=3 ;

--
-- Dumping data for table `datetable`
--

INSERT INTO `datetable` (`dateid`, `datestuff`) VALUES
(1, '2012-10-02'),
(2, '2012-10-04');

PHP CODE (FILE)

   <?php
//Connect to your host
$con = mysql_connect("localhost","admin","admin");
if (!$con)
  {
  die('Could not connect: ' . mysql_error());
  }
//select your database
mysql_select_db("my_db", $con);

//getting today's date and formating it, output is like this (4-10-2012)
$today = date('j-m-Y');

//query your table, also date has been formated like this (4-10-2012)
$result = mysql_query("SELECT DATE_FORMAT( CURDATE( ) ,  '%e-%m-%Y' ) AS today, DATE_FORMAT( datestuff,  '%e-%m-%Y' ) AS datestuff FROM datetable WHERE CURDATE( ) = datestuff");

//get the resultset
while($row = mysql_fetch_array($result))
  {
  echo "date in table: ".$row['datestuff']. "---- today's date: ". $row['datestuff'];
  echo "<br />";
  }
?>

Try it out let me know if it worked out for you….