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Asked: 2026-05-22T00:18:56+00:00

Possible Duplicate: mysql_fetch_array() expects parameter 1 to be resource, boolean given in select I

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Possible Duplicate:
mysql_fetch_array() expects parameter 1 to be resource, boolean given in select

I am getting Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in C:\wamp\www\FBlike\like.php on line 104 in my script..
I’m not sure what that means and why it is happening.. help :)?

$like_id=mysql_real_escape_string($_GET['id']);

$sql=mysql_query("select * from likes WHERE id=$like_id DESC LIMIT 1");
while($row=mysql_fetch_array($sql))
{
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">

<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />

   <meta name="description" content="<?php print $row['like']; ?>"/>

  <meta name="keywords" content="<?php print $row['like']; ?>" />

    <meta property="og:description" content="Click to See More..." />

      <meta property="fb:app_id" content="" />



   <meta property="og:title" content="<?php print $row['like']; ?>"/>

   <meta property="og:type" content="activity"/>

     <meta property="og:url" content="http://www.fbquote.me/like.php?id=<?php print $row['id']; ?>" />

  <meta property="og:site_name" content="pDank" />
<title><?php print $row['like']; ?></title>

<?php } ?>
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1 Answer

  1. Editorial Team

    You have an error in your SQL query.

    Add the following code before mysql_fetch_array():

    if (!$sql) {
    die(mysql_error());
}
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