Question

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one variable row inside another variable row

I have script something like –

$sql = "SELECT * FROM `users`"
$q = mysql_query($sql) or die(mysql_error());
$row = mysql_fetch_array($q);
$sql1 = "SELECT * FROM `other_table`";
$q1 = mysql_query($sql1) or die(mysql_error());
$row1 = mysql_fetch_array($q1);
$item = $row1[$row['username']];

How can I set one variable row inside another, since it don’t work. Basically, I need to select username, and then select column with user username from other table, in which is written user points.

I was thinking about adding –

$sql = "SELECT * FROM `users`"
$q = mysql_query($sql) or die(mysql_error());
$row = mysql_fetch_array($q);
$sql1 = "SELECT `".$row['username']."` FROM `other_table` WHERE `uid` = 1";
$q1 = mysql_query($sql1) or die(mysql_error());
$row1 = mysql_fetch_array($q1);
$item = $row1[xxxxxxxxxx]; // DONT KNOW HOW TO DEFINE IT, so it takes out found variable (there is only one).

I have question already, but not with full info, and I don’t know how to delete it :(!

Here is my table –

Users

‘id’–‘name’
‘1’–‘Bil’
‘2’–‘Conor’
‘3’–‘Ilian’

Other_table (which holds points for users)

‘id’–‘Bil’–‘Conor’–‘Ilian’
‘1’–‘2’–‘3′–’55’

Don’t ask, why I don’t hold the points in the same table, since if I could, I would do that ;)!

Answer 1

It sounds like you need to redesign the tables to start with, I would suggest a table structure like this:

Table Users
ID | Name

Table Points
UserID | Points

This way you can add a foreign key constraint between the tables and then do a simple join query like:

SELECT U.Name, P.Points FROM Users AS U INNER JOIN Points AS P ON U.ID = P.UserID

Then your php code would look like:

$sql = "SELECT U.Name, P.Points FROM Users AS U INNER JOIN Points AS P ON U.ID = P.UserID";
$q = mysql_query($sql) or die(mysql_error());
$row = mysql_fetch_array($q);

Here are the create table queries for you:

CREATE TABLE Users (ID INT NOT NULL AUTO_INCREMENT,
    Name VARCHAR(50) NOT NULL, PRIMARY KEY (ID))
CREATE TABLE Points (UserID INT NOT NULL, Points INT,
    FOREIGN KEY(UserID) REFERENCES Users(ID) ON UPDATE CASCADE ON DELETE CASCADE)

EDIT:

This should allow you to get the value (NOTE: untested as I don’t have a php/mysql instance to mess with currently), but for a more robust solution you really should look into redesigning your table schema.

$userName = $row['username'];
$sql1 = "SELECT [". $userName ."] FROM other_table WHERE [uid] = 1";
$q1 = mysql_query($sql1) or die(mysql_error());
$row1 = mysql_fetch_array($q1);
$item = $row1[$userName];