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Home/ Questions/Q 7086001
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T07:29:42+00:00 2026-05-28T07:29:42+00:00

Possible Duplicate: Operator overloading I didn’t find any thing that could help me in

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Possible Duplicate:
Operator overloading

I didn’t find any thing that could help me in this subject…
I’m trying to over load the << operator, this is my code:

 ostream& Complex::operator<<(ostream& out,const Complex& b){
    out<<"("<<b.x<<","<<b.y<<")";
    return out;
}    

this is the declaration in the H file:

 ostream& operator<<(ostream& out,const Complex& b);

I get this error:
error: std::ostream& Complex::operator<<(std::ostream&, const Complex&) must take exactly one argument

what and why I’m doing wrong?
thanks

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  1. Editorial Team
    Editorial Team
    2026-05-28T07:29:43+00:00Added an answer on May 28, 2026 at 7:29 am

    your operator << should be free function, not Complex class member in your case.

    If you did your operator << class member, it actually should take one parameter, which should be stream. But then you won’t be able to write like

    std::cout << complex_number;
    

    but

    complex_number << std::cout;
    

    which is equivalent to

    complex_number. operator << (std::cout);
    

    It is not common practice, as you can note, that is why operator << usually defined as free function.

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