Question

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Oracle SQL – How to Retrieve highest 5 values of a column

I have a simple question for someone who knows anything about SQL but since i’m very new and although I have tried many different ways, I can never seem to get the syntax correct. I want to display only the average hotel which is the MAX result. Currently it displays the average of all the hotels individually. Is this something I can use the MAX function for? I am using oracle

SELECT HOTEL.H_NAME "HOTEL NAME", ROUND(AVG (R_PRICE), 1) "AVERAGE ROOM PRICE"
FROM ROOM JOIN HOTEL ON HOTEL.HOTEL_NO = ROOM.HOTEL_NO
WHERE HOTEL.H_NAME = 'Shangra_La'
OR HOTEL.H_NAME = 'Hilton'
OR HOTEL.H_NAME = 'Sheraton'
GROUP BY HOTEL.H_NAME
ORDER BY HOTEL.H_NAME;

Answer 1

In Oracle you can use the ROWNUM pseudo column.

SELECT * FROM
(
    SELECT 
        HOTEL.H_NAME "HOTEL NAME", 
        ROUND(AVG (R_PRICE), 1) "AVERAGE ROOM PRICE" 
    FROM
        ROOM 
            JOIN HOTEL ON HOTEL.HOTEL_NO = ROOM.HOTEL_NO 
    WHERE HOTEL.H_NAME IN ('Shangra_La','Hilton','Sheraton')
    GROUP BY HOTEL.H_NAME 
) v
WHERE ROWNUM = 1
ORDER BY "AVERAGE ROOM PRICE" DESC;