Question

Possible Duplicate:
Pass two integers as one integer

Will this work in Objective-C?
Pass two integers as one integer

If so, how do I do it with NSInteger?

I’m asking because I want to calculate a unique NSInteger tag from the NSUIntegers row & section of a UITableView?

See, I’m dealing with a UITableViewController that has three sections, which each have multiple rows. Every row has a UISwitch, and each UISwitch is linked to the same target-action method, switchAction:.

In switchAction:, my plan is to inspect the sender‘s tag to figure out the UISwitch‘s NSIndexPath (section & row) of the UITableView.

So, I want two methods like:

+ (NSInteger)integerFromInteger1:(NSInteger)int1 integer2:(NSInteger)int2;
+ (NSIndexPath *)indexPathFromInteger:(NSInteger)integer;

The first method may work better written in C. That works too if you prefer.

Answer 1

Based on @benzado’s answer, I came up with a beautiful solution for how to get the index path of the UISwitch that sent the switchAction: message.

- (void)switchAction:(id)sender {
    UISwitch *onOff = (UISwitch *)sender;
    NSIndexPath *indexPath = [self.tableView indexPathForCell:
                              (UITableViewCell *)[onOff superview]];
    // carry on...
}

No tags necessary. Just keep your pants on.