Question

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PHP Error: mysql_fetch_array() expects parameter 1 to be resource, boolean given

I am trying to build an array from a mysql object after querying.

The number or rows returned in the query is 68, this is why I thought a forloop would be good. However php does not like my code inside the forloop.

Here is the code:

$result = $db->query("SELECT * FROM `networktariff`");


        $rows = mysql_num_rows($result);

        for ($i= 0; $i<$rows; $i++)
        {

            $tariffs[$i] = mysql_fetch_assoc($result[$i]);


        }

I am getting an error message saying :

Warning: mysql_fetch_assoc() expects parameter 1 to be resource, null given in /usr/local/www/apache22/data/quote/index.php on line 58

Answer 1

There is no such thing like "mysql object".
Your $db object belongs to some user-defined class and there is no point in asking anyone about this class’ behavior.

Assuming that query() method just utilizing ordinary mysql_query() function call, it does return a resource, not object.

If you have a strange idea of using some class to run the query yet bare API functions for the rest,

$tariffs = array();
$result = $db->query("SELECT * FROM `networktariff`");
while ($row = mysql_fetch_assoc($result) {
  $tariffs[] = $row;
}

I dunno though why your class doesn’t have some helper function to get the whole data at once, something like

$tariffs = $db->query2arr("SELECT * FROM `networktariff`");