Question

Possible Duplicate:
PHP get all arguments as array?

Well,

In java I can do this (pseudocode):

public hello( String..args ){
    value1 = args[0] 
    value2 = args[1] 
    ...
    valueN = arg[n];
}

and then:

hello('first', 'second', 'no', 'matter', 'the', 'size');

Is something like this in php?

EDIT

I now that I can pass an array like hello(array(bla, bla)), but may could exists the way mencioned above, right?

Answer 1

See func_get_args:

function foo()
{
    $numArgs = func_num_args();

    echo 'Number of arguments:' . $numArgs . "\n";

    if ($numArgs >= 2) {
        echo 'Second argument is: ' . func_get_arg(1) . "\n";
    }

    $args = func_get_args();
    foreach ($args as $index => $arg) {
        echo 'Argument' . $index . ' is ' . $arg . "\n";

        unset($args[$index]);
    }
}

foo(1, 2, 3);

EDIT 1

When you call foo(17, 20, 31) func_get_args() don’t know that the first argument represents the $first variable for example. When you know what each numeric index represents you can do this (or similar):

function bar()
{
    list($first, $second, $third) = func_get_args();

    return $first + $second + $third;
}

echo bar(10, 21, 37); // Output: 68

If I want a specific variable, I can ommit the others one:

function bar()
{
    list($first, , $third) = func_get_args();

    return $first + $third;
} 

echo bar(10, 21, 37); // Output: 47