Question

Possible Duplicate:
PHP: “Notice: Undefined variable” and “Notice: Undefined index”

I have a member.php page which contains this piece of code:

<?php
    if (isset($_SESSION['teacherusername'])) 
    {
        $username = $_SESSION['teacherusername'];
    }
?>

Now in the teacherlogin.php I use “include” to include the code from the member.php page. The problem I have is that if I open up the teacherlogin.php page, it gives me an undefined variable error stating:
Notice: Undefined variable: username in ... on line 25

Why is it stating it is undefined because I have defined it in the member.php page?

Below is the code in the teacherlogin.php:

<?php
  // PHP code
  session_start(); 

    ini_set('display_errors',1); 
 error_reporting(E_ALL);

// connect to the database
include('connect.php');
include('member.php');

  /* check connection */
  if (mysqli_connect_errno()) {
    printf("Connect failed: %s\n", mysqli_connect_error());
    die();
  }

  // required variables (make them explciit no need for foreach loop)
  $teacherusername = (isset($_POST['teacherusername'])) ? $_POST['teacherusername'] : '';
  $teacherpassword = (isset($_POST['teacherpassword'])) ? $_POST['teacherpassword'] : '';
  $loggedIn = false;
  $active = true;

  if ($username){
      echo "You are already Logged In: <b>{$_SESSION['teacherforename']} {$_SESSION['teachersurname']}</b> | <a href='./teacherlogout.php'>Logout</a>";
  }
  else{

echo "Please Login";

}

?>

Answer 1

The variable $username is only set by your member.php when the user is logged in. Try using if(isset($username)) instead of if($username) in your teacherlogin.php.