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Home/ Questions/Q 8675651
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Editorial Team
  • 0
Editorial Team
Asked: June 12, 20262026-06-12T20:00:11+00:00 2026-06-12T20:00:11+00:00

Possible Duplicate: PHP: Notice: Undefined variable and Notice: Undefined index I know its basic

  • 0

Possible Duplicate:
PHP: “Notice: Undefined variable” and “Notice: Undefined index”

I know its basic but I’ve been up for 8 hours coding and this has gotten me stuck. Receiving an undefined index for all my posts on line 14 for my update query. I would appreciate any help in the matter thanks.

<html>
<head>  
</head>
<body>
<h1><center><i>Edit/Add Course ID</i></center></h1>
<?php 
$con = mysql_connect("localhost","u/n","p/w");
if (!$con){
die ("Can not connect: " . mysql_error());
}
mysql_select_db("my_db",$con);

if(isset($_POST['submit'])){
$UpdateQuery = "UPDATE course SET cours_num='$_POST[coursnum]', 
cours_title='$_POST[courstitle]', cours_desc='$_POST[coursdesc]' WHERE 
cours_num='$_POST[hidden]'";
mysql_query($UpdateQuery, $con);

};
$sql = "Select * FROM course";
$myData = mysql_query($sql,$con);

while($record = mysql_fetch_array($myData)){
echo "<form action=mydata.php method=post>";
echo "<b>Course Number:</b></br>";
echo "<input type=text maxlength=10 size=10 readonly name=coursnum value=" . 
$record['cours_num'].">";
echo "</br></br>";
echo "<b>Course Title:</b><br/>";
echo "<input type=text maxlength=10 size=10 name=courstitle value=" . 
$record['cours_title'].">";
echo "</br></br>";
echo "<b>Course Description:</b></br>";
echo "<input type=text name=coursdesc max length=50 size=50 value=" . 
$record['cours_desc'].">";
echo "</br></br>";
echo "<input type=hidden name=hidden value=" . $record['cours_num'].">";
echo "<center><input type=submit name=submit value=Edit></center>";
echo "</form>";
}

mysql_close($con);

?>
</body>
</html>
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  1. Editorial Team
    Editorial Team
    2026-06-12T20:00:13+00:00Added an answer on June 12, 2026 at 8:00 pm

    You are getting error due to the following line

    $UpdateQuery = "UPDATE course SET cours_num='$_POST[coursnum]', 
    cours_title='$_POST[courstitle]', cours_desc='$_POST[coursdesc]' WHERE 
    cours_num='$_POST[hidden]'";
    

    You can use

    $UpdateQuery = sprintf("UPDATE course SET cours_num='%d' , 
                    cours_title='%s', 
                    cours_desc='%s',
                    WHERE  cours_num = '%d'", mysql_real_escape_string($_POST['coursnum']), mysql_real_escape_string($_POST['courstitle']), mysql_real_escape_string($_POST['coursdesc']), mysql_real_escape_string($_POST['hidden']));
    

    You should also make sure your variables are always set

    Example

    $_POST['coursnum'] = isset($_POST['coursnum']) ? $_POST['coursnum'] : null ;
    
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