Question

Possible Duplicate:
PHP str_replace with for loop from array

How to replace a string (#stringA#) with elements from an array?… let’s say we’ve a text:

'My shoes are #stringA# but #stringA#' (the same string – #stringA#)

with $array:

$array[0] = 'comfy';
$array[1] = 'smells horrible';

so it’ll be equal to 'My shoes are ' . $array[0] . ' but ' . $array[1]; – My shoes are comfy but smells horrible?

Answer 1

Usually in cases like this, you’d use %s as the string replacement and then use vsprtinf() to replace the occurances of %s with values from an array. However, in a simple case like yours, you can also just replace the search strings with %s and achieve the same effect. For example:

<?php

$string = 'My shoes are #stringA# but #stringA#';
$key = "#stringA#";

$array[0] = 'comfy';
$array[1] = 'smells horrible';

$string = str_replace(array('%', $key), array('%%', '%s'), $string);
$newstring = vsprintf($string, $array);

echo $newstring;

?>

(The replacement of % to %% is to avoid any problems with printf symbols in general case)