Question

Possible Duplicate:
php variable as conditional assignment

I am trying to concatenate a conditional assignment through php variables like this

$cndtnal='&& $x==4';

if($y==5 eval($cndtnal)){
   print 'Hello World';
}

But I am getting a Parse error: syntax error, unexpected $end in : eval()’d code on line 1.

I have tried too :

$cndtnal='&& $x==4';

if (eval('$y==5'.$cndtnal)){
       print 'Hello World';
    }

But I get the same error.

Thanks.

Answer 1

You’re missing return and a semicolon.

But really, you should avoid eval.

<?php
$foo = 1;
$bar = 2;
$test = ' && $bar == 2';
if(eval('return $foo == 1' . $test . ';')) {
    echo "That horribly eval()'d code worked!";
}
?>