Question

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PHP – Why is a concatenated print_r printed out of order?

the following is a piece of code which has $input in the format of S:2:0;M:7:9;L:4:9;XL:6:0;XXL:6:9 these are parsed and stored into the 2d array .. by the following code

    $stock_data = explode(';', $input);
    foreach($stock_data as $value) {
        $value = explode(':', $value);

        if (!empty($value[0])) {

            $temp_size = $value[0];
            $stock[$value[0]] = array('winkel' => $value[1], 'distributeur' => $value[2]);

            fb('afetr array val = '.$temp_size.' = its val -|'. print_r($stock[$temp_size]['distributeur']).'|',FirePHP::INFO);
        }
    }

    return $stock;

the values in the print_r($stock[$temp_size]['distributeur'] or print_r($stock[$temp_size]['winkel'] is always 1, even if later i try to print_r the whole array $stock, all it has got is 1.

I was trying for print_r() to show the array as it should be, What is going wrong here.

Answer 1

That’s because that’s what print_r returns. If you want it to return the string, add the 2nd parameter:

print_r($stock[$temp_size]['distributeur'], true)