Question

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postfix 'd+0' in Fortran real literal expressions

I have this code line in Fortran 90:

OVERN2 = 1.d+0/DBLE(FLOAT(NMODE2))

NMODE2 is an integer, OVERN2 is a REAL*8.

Can you please explain to me what this line does? I don’t understand the .d+0/ part?
if you can also translate that to C or any other easier language.

Answer 1

1.d+0 is just a double precision literal in scientific notation, i.e. 1.0e0 or just 1.0.

In C it would be:

double overn2 = 1.0 / (double)nmode2;