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Asked: 2026-06-12T11:05:28+00:00

Possible Duplicate: Preg Replace – replace second occurance of a match I have a

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Possible Duplicate:
Preg Replace – replace second occurance of a match

I have a string that includes the word rules twice. I need to find and replace the 2nd word. Tried fooling around with str_replace() but couldn’t get anything, the 4th parameter wasn’t what I expected.

Here is an example string:

http://localhost/proj1/modstart/admin/index.php?i=rules&sid=397ab1f6b8eb8a17787438a7e2e60ea3&mode=rules

After my replace it should look like this:

http://localhost/proj1/modstart/admin/index.php?i=rules&sid=397ab1f6b8eb8a17787438a7e2e60ea3&mode=manage

I read that preg_replace() could help, but I don’t know how to write patterns.

Ideas?

P.S: Don’t suggest splitting the string into two variables, that wouldn’t serve my needs.

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1 Answer

  1. Editorial Team

    It would be a very good idea to learn about regular expressions. In PHP, you can accomplish your find/replace like this:

    $result = preg_replace('/(rules.*?)rules/','$1manage',$str,1);

    It basically finds “rules” once, then anything, then rules a second time, then puts it all back before the second match and replaces the word.

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