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Home/ Questions/Q 7646587
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T10:14:51+00:00 2026-05-31T10:14:51+00:00

Possible Duplicate: Question about C# covariance Why does the code compile in the first

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Possible Duplicate:
Question about C# covariance

Why does the code compile in the first case, but doesn’t compile in the second one?

class ClassA {
}

class ClassB : ClassA {
}

static void Main() {
    var classAList = new List<ClassA>();
    var classBList = new List<ClassB>();

    IEnumerable<ClassA> classAIEnumerable;
    IEnumerable<ClassB> classBIEnumerable = new List<ClassB>();

    // First case:
    classAIEnumerable = classBIEnumerable;

    // Second case:
    classAList = classBList;
}

What does prevent code to compile in the second case? Why can’t compiler figure out that this casting is safe?

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  1. Editorial Team
    Editorial Team
    2026-05-31T10:14:52+00:00Added an answer on May 31, 2026 at 10:14 am

    List<T> is not covarient because it does not define T as an out type unlike IEnumerable<out T>. It is also not contravarient because it does not define T as an in.

    If that cast were allowed then you could add a class C to it:

    class ClassC : ClassA { 
    } 
    
    // Second case: 
    classAList = classBList; //suppose this is allowed
    ClassA myC = new ClassC();
    classAList.Add(myC); //Whoops! we've added a ClassC to the list which is actually a list of ClassBs
    

    http://msdn.microsoft.com/en-us/library/ee207183.aspx

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