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Home/ Questions/Q 7167173
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T14:32:05+00:00 2026-05-28T14:32:05+00:00

Possible Duplicate: Random number generator not working the way I had planned (C#) I

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Possible Duplicate:
Random number generator not working the way I had planned (C#)

I have this code in c# but I get a result the same number, what is it wrong?

like a21, a21, a21….

        String c = "";
        int randomNumber = 0;
        for (int i = 0; i < 20; i++)
        {
            randomNumber = RandomNumber(0, 617);
            c += "a " + randomNumber + ", ";                    
        }
        file.WriteLine(c);



I am using this function

public static int RandomNumber(int min, int max)
    {
        Random random = new Random();
        return random.Next(min, max);
    }
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  1. Editorial Team
    Editorial Team
    2026-05-28T14:32:06+00:00Added an answer on May 28, 2026 at 2:32 pm

    You should pass the Random as parameter to your function. Although your function has no added value then anymore.

    var rnd = new Random();
    for (int i = 0; i < 20; i++)
    {
        randomNumber = RandomNumber(rnd ,0, 617);
        c += "a " + randomNumber + ", ";                    
    }
    
    public static int RandomNumber(Random rnd, int min, int max)
    {
        return rnd.Next(min, max);
    }
    

    Every time you do new Random() it is initialized using the clock. This means that in a tight loop you get the same value lots of times. You should keep a single Random instance and keep using Next on the same instance.

    https://stackoverflow.com/a/768001/284240

    Edit: i read in your comment that you want to create 20 unique numbers in the given range, here is one way using HashSet<int>:

    HashSet<int> uniqueNumber = new HashSet<int>();
    var rnd = new Random();
    while(uniqueNumber.Count<20){
        var nextNum = rnd.Next(0, 617);
        uniqueNumber.Add(nextNum);
    }
    
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