Question

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Remove entire word if the word contains specific string

How I can remove an entire word that contains a word?
For example, ‘releas’ should delete released, releases releasing etc.

/* Read in from the file here, not in the function - you only need to read the file once */
$wordlist = array('release','announce');

/* Sample data */
$words = 'adobe releases releases Acrobat X';

foreach ($wordlist as $v)
      $words = clean($v,$words);

function clean($wordlist,$value)
{
        return preg_replace("/\b$wordlist\b/i", '***',trim($value));
}  

echo 'Words: '.$words.PHP_EOL;

Answer 1

You can loop through your $wordlist

function clean($wordlist,$value)
{
    foreach ($wordlist as $word) {
        $value = preg_replace("/\b\w*$word\w*\b/i", '***', trim($value));
    }

    return $value;
}  

and doing it in one replace

function clean($wordlist,$value)
{
    $all_words = implode('|', $wordlist);
    return preg_replace("/\b\w*(?:$all_words)\w*\b/i", '***', trim($value));
}

Update:

Looking through other answers and comments, it seems I haven’t looked properly at the question. If $wordlist is not an array, you can just use @fthiella’s answer.