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Home/ Questions/Q 9138927
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T09:19:14+00:00 2026-06-17T09:19:14+00:00

Possible Duplicate: Replacing all non-alphanumeric characters with empty strings import java.util.Scanner; import java.util.regex.*; public

  • 0

Possible Duplicate:
Replacing all non-alphanumeric characters with empty strings

import java.util.Scanner;
import java.util.regex.*;
public class io{
public static void main(String args[]){
Scanner scan = new Scanner(System.in);
String c;
if((c=scan.nextLine())!=null)
 {
Pattern pt = Pattern.compile("[^a-zA-Z0-9]");
Matcher match= pt.matcher(c);
    while(match.find()){
         c=c.replace(Character.toString(c.charAt(match.start())),"");
         }
    System.out.println(c);
      }
   }
}

Case 1

Input : hjdg$h&jk8^i0ssh6
Expect : hjdghjk8i0ssh6
Output : hjdgh&jk8^issh6

Case 2

Input : hjdgh&jk8i0ssh6
Expect : hjdghjk8i0ssh6
Output : hjdghjk8i0ssh6

Case 3

Input : hjdgh&j&k8i0ssh6
Expect : hjdghjk8i0ssh6
Output : hjdghjki0ssh6

Anyone please help me to figure out, what is wrong in my code logic ??

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-17T09:19:15+00:00Added an answer on June 17, 2026 at 9:19 am

    use [\\W+] or "[^a-zA-Z0-9]" as regex to match any special characters and also use String.replaceAll(regex, String) to replace the spl charecter with an empty string. remember as the first arg of String.replaceAll is a regex you have to escape it with a backslash to treat em as a literal charcter.

              String c= "hjdg$h&jk8^i0ssh6";
            Pattern pt = Pattern.compile("[^a-zA-Z0-9]");
            Matcher match= pt.matcher(c);
            while(match.find())
            {
                String s= match.group();
            c=c.replaceAll("\\"+s, "");
            }
            System.out.println(c);
    
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