Question

Possible Duplicate:
ROT-13 function in java?

I have to shift all char from a string 13 places in the alphabet

private static String encode(String line) {
    char[] toEncode = line.toCharArray();
    for (int i = 0; i < toEncode.length; i++) {
        if (Character.isLetter(toEncode[i])) {
            toEncode[i] += 13;
        }
    }
    line = String.valueOf(toEncode);
    return line;
}

The Problem is that for example ‘z’ get to a ?. How can I solve that?

Thx for help.

Answer 1

It is because next chars after ‘z’ is punctuation chars and so on. You can shift so that ‘z’ will be ‘n’ for example.

toEncode[i] = (toEncode[i] + 13 - (int)'a') % 26 + (int)'a';