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Home/ Questions/Q 8517631
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T05:45:27+00:00 2026-06-11T05:45:27+00:00

Possible Duplicate: SQL Server 2008 Generate a Series of date times I have to

  • 0

Possible Duplicate:
SQL Server 2008 Generate a Series of date times

I have to Loop through a startDate and endDate

The SELECT statement should produce result as..

Expected Output :

------------
Date
------------
09/01/2012 -> startDate
09/02/2012
09/03/2012
.
.
.
.
09/30/2012 -> endDate

i tried

declare @startDate datetime , @endDate endDate
set @startDate='09/01/2012'
set @endDate='09/30/2012'

while DATEDIFF(@startDate,@endDate)!=-1
begin
select @startDate as Date
set @startDate = DATEADD(day,2,@startDate)
end

But its not working out..

it generates 30 outputs..

i want the dates in a single output as in the expected output..

where am i going wrong here guys ?

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  1. Editorial Team
    Editorial Team
    2026-06-11T05:45:29+00:00Added an answer on June 11, 2026 at 5:45 am

    That will give you a resultset for each loop iteration as you select per iteration.

    If you want a single resultset insert into a temp table/variable per iteration then select from it or

    ;with T(day) as
    (
        select @startDate as day
            union all
        select day + 1
            from T
            where day < @endDate
    )
    select day as [Date] from T
    
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