Question

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String equality vs equality of location

This my first question, be patient with me, please

I have the following code:

String str1 = "hello";
String str2 = "hello";
System.out.println(str1 == str2);

And the result is true

Why?

Answer 1

When Java finds same literals during compile time it creates a single instance of it and refers that to all the references.

str1 and str2 both have same literals “hello” so jvm creates a single instance of it and assigns it to str1 and str2.

So when you do str1==str2 you get true. (Both are referencing to the same instance)