Question

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Turning long fixed number to array Ruby

Well, I have to iterate over the digits of a integer in Ruby. Right now I was just splitting it up into an array, and then iterating over that. However I was wondering if there was a faster way to do this?

Answer 1

The shortest solution probably is:

1234.to_s.chars.map(&:to_i)
#=> [1, 2, 3, 4]

A more orthodox mathematical approach:

class Integer
  def digits(base: 10)
    quotient, remainder = divmod(base)
    quotient == 0 ? [remainder] : [*quotient.digits(base: base), remainder]
  end
end

0.digits #=> [0]
1234.digits #=> [1, 2, 3, 4]
0x3f.digits(base: 16) #=> [3, 15]