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Home/ Questions/Q 3437738
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T08:06:06+00:00 2026-05-18T08:06:06+00:00

Possible Duplicate: Undefined, unspecified and implementation-defined behavior I’m trying to deepen my understanding of

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Possible Duplicate:
Undefined, unspecified and implementation-defined behavior

I’m trying to deepen my understanding of undefined behavior in C++. Suppose a C++ compiler will intentionally detect some cases of undefined behavior – for example, modifying the variable twice between two sequence points:

x++ = 2;

Once that imaginary compiler reliably detects such a situation it will say emit ten totally random machine instructions into the produced machine code.

According to C++ standard, wherever something is classified as UB there’re no requirements on what happens. Will the described imaginary compiler be conformant to the C++ standard?

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  1. Editorial Team
    Editorial Team
    2026-05-18T08:06:07+00:00Added an answer on May 18, 2026 at 8:06 am

    Yes. The standard imposes no requirements, so it can do whatever it wants:

    undefined behavior

    behavior, such as might arise upon use of an
    erroneous program construct or
    erroneous data, for which this
    International Standard imposes no
    requirements.

    Just as a note, that is undefined behavior, but it’s not necessarily a good example. On g++ 4.4.1, it will refuse to compile with:

    error: lvalue required as left operand
    of assignment

    because the result of a post-increment is not an lvalue.

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