Question

Possible Duplicate:
Understanding which constructor is chosen and why

Why compiler acts like this,

public class  Calculator{

    private Calculator(Object o) {
        // code goes here
    }

    private Calculator(double[] calc) {
        // code goes here
    }

    public static void main(String[] args) {
        new Calculator(null);
    }
}

This program executes second constructor. Why first constructor not execute?

Answer 1

Both constructors are accessible and applicable.

The constructor Calculator (Object) accepts any parameter passed to Calculator (double[]), so Calculator (Object) is less specific.