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Home/ Questions/Q 6862201
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T02:37:56+00:00 2026-05-27T02:37:56+00:00

Possible Duplicate: Varying behavior for possible loss of precision Code Sample A public class

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Possible Duplicate:
Varying behavior for possible loss of precision

Code Sample A

 public class Test {                                                         
     public static void main(String[] args) {
         int i = 0;
         i = i + 1.5;
     }
 }

Code Sample B

 public class Test {                                                         
     public static void main(String[] args) {
         int i = 0;
         i += 1.5;
     }
 }

Unsurprisingly, compiling A produces the error below. Surprisingly, compiling B produces no error and it appears to behave as if I inserted an explicit cast to integer before the double value 1.5. Why in the world does this happen? This goes against everything I thought I knew!

Test.java:6: possible

 loss of precision

    found   : double
    required: int
            i = i + 1.5;
                  ^
    1 error
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  1. Editorial Team
    Editorial Team
    2026-05-27T02:37:57+00:00Added an answer on May 27, 2026 at 2:37 am

    It is working as designed. The compound operators add an implicit cast to the operation. Otherwise you have to use an explicit cast.

    More info?

    http://docs.oracle.com/javase/specs/jls/se7/html/jls-15.html#jls-15.26.2

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