Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
Possible Duplicate:
what does #someDiv mean?
i am doing this:
onmouseover="evt.target.setAttribute('opacity', '0.5'); $('#someDiv').show();" onmouseout="evt.target.setAttribute('opacity','1)'); $('#someDiv').hide();"
but i guess i need something called an ID selector?
anyway how do i make it so that when there is a mouseover the object, i get a little popup ?
$('#someDiv')is selecting the element withID="someDiv", so selectors might not be your problem.Apart from using the onmouseover event attribute, the code you provided should basically work. Are you seeing any JS errors, or have other debug results you could share?
Edit:
It’s probably (maybe?) unrelated to your problem, but you should consider moving all the JS logic to a linked JS file instead of using the onmouseover property. jQuery’s $(‘#your-selector’).mouseover() method is a much better way to handle this. (http://api.jquery.com/mouseover/)