Question

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What does the >?= operator mean?

I was wondering what is the <?= operator I keep seeing in C++ code. It doesn’t compile on my system, but I’m sure it is correct. It’s used like this:a <?= something;

Also, what would I need to do to be able to compile it?

EDIT POST:

Please see this source code (it is a solution of the problem Square Fields (Problem B) of the winner of a practice Google Code Jam contest — see here). I saw the same pattern of characters in some other submissions too.

#include<cstdio>
#include<algorithm>
#include<iostream>
#include<sstream>
#include<string>
#include<vector>
#include<set>
#include<map>
#include<numeric>
#include<cmath> using namespace std;

#define ALL(t) t.begin(),t.end()
#define FOR(i,n) for (int i=0; i<(int)(n); i++)
#define FOREACH(i,t) for (typeof(t.begin()) i=t.begin(); i!=t.end(); i++) typedef vector<int> vi; typedef long long int64;

int t[15][1<<15]; int main() {   int N;cin>>N;   for(int c=1;c<=N;c++){
    int n,k,x[30],y[30];
    cin>>n>>k;
    FOR(i,n)cin>>x[i]>>y[i];
    FOR(take,1<<n)if(take){
      int minx=1000000,maxx=-1,miny=1000000,maxy=-1;
      FOR(i,n)if(take&1<<i)minx<?=x[i],maxx>?=x[i],miny<?=y[i],maxy>?=y[i];
      t[1][take]=(maxx-minx)>?(maxy-miny); //      cout<<take<<" "<<t[1][take]<<endl;
    }
    for(int kk=2;kk<=k;kk++)FOR(take,1<<n){
      t[kk][take]=t[kk-1][take];
      for(int take2=take;take2;take2=(take2-1)&take)
        t[kk][take]<?=t[kk-1][take-take2]>?t[1][take2];
    }
    cout<<"Case #"<<c<<": "<<t[k][(1<<n)-1]<<endl;   }   return 0; }

Answer 1

EDIT:

Its an extension in older versions of GCC. See this :

What does the >?= operator mean?

But then the extensions are <? and >? . I still don’t see <?=.

6.1 Minimum and Maximum Operators in C++

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EARLIER POST:

I assure you, there is no such operator in C++. Its certainly a mistyping.

The programmer most likely wanted to type either <= or ?:

Or maybe you mistyped it here when in fact you intended to type a digraph or trigraph (but what you’ve typed is neither digraph nor trigraph).

As you yourself said it doesn't compile on my system. How would it? Its a typo.