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Asked: 2026-06-17T08:56:51+00:00

Possible Duplicate: What does this C++ code mean? What does ‘unsigned temp:3’ mean? I

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Possible Duplicate:
What does this C++ code mean?
What does ‘unsigned temp:3’ mean?

I have seen one small c program recently.There in that program,the structure was declared in this manner which I could not understand.

struct
{
mynode *node;
unsigned vleft :1; 
unsigned vright :1; 
}save[100];

Here node is pointer to some other structure.

Can some one please explain what unsigned vleft :1; unsigned vright :1; are? And I could not find any datatype assigned to vleft and vright.What is the reason for that?

Thanks.

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1 Answer

  1. Editorial Team

    The default type assumed here is unsigned int, this is assumed by the compiler when you specify just unsigned.

    The bitfield syntax unsigned vleft : 1 specifies the width in bits of the data field, in this situation it means that it’s a single bit flag (which can be either 0 or 1). This is used to pack many fields of the structure in less bits (when you don’t need to waste, like in this case, a whole char or int for just storing a flag).

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