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Home/ Questions/Q 3633988
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Editorial Team
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Editorial Team
Asked: May 19, 20262026-05-19T00:43:22+00:00 2026-05-19T00:43:22+00:00

Possible Duplicate: What is Inversion of Control? I understand what Dependency Injection (DI) is

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Possible Duplicate:
What is Inversion of Control?

I understand what Dependency Injection (DI) is (I think!). It’s basically the satisfying of dependencies that an object may have. I try to think of the code I write when using DI as service oriented and I define my code as using other services.

However, I’m currently wondering what it is exactly that we’re inverting the control of, when using IoC. It’s a fairly vague term and it could mean a couple of things.

But, I think it’s the responsibility of creating the object (and therefore satisfying dependencies using DI) which is handled by the IoC framework.

It is still the responsibility of the application to ask for objects (ie – services) that it uses, the distinction being that it doesn’t know (or care) how to create it. So, why is service locator considered an anti-pattern if all it’s doing is asking for a service?

Have I got that correct? Or does it mean something else. Also, have I got the responsibilities of DI and IoC separated correctly? If I have then an IoC framework cannot function without a DI framework. Or is DI just a feature of IoC frameworks?

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  1. Editorial Team
    Editorial Team
    2026-05-19T00:43:22+00:00Added an answer on May 19, 2026 at 12:43 am

    Dependency injection generally means passing a dependent object as a parameter to a method, rather than having the method create the dependent object. What it means in practice is that the method does not have a direct dependency on a particular implementation; any implementation that meets the requirements can be passed as a parameter.

    Inversion of control simply recognizes that the dependency relationship is reversed. Instead of A depending on B by way of creating, implementing, or calling it directly, A receives B as a parameter, and is no longer responsible for B in any way.

    Implementing parameter types as interfaces simplifies the process, and generalizes it, but it’s not strictly necessary.

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