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Editorial Team
Asked: May 15, 20262026-05-15T05:02:14+00:00 2026-05-15T05:02:14+00:00

Possible Duplicate: what is the difference between (.) dot operator and (->) arrow in

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Possible Duplicate:
what is the difference between (.) dot operator and (->) arrow in c++

in this book i have I’m learning pointers, and i just got done with the chapter about OOP (spits on ground) anyways its telling me i can use a member selection operator like this ( -> ). it sayd that is is like the “.” except points to objects rather than member objects. whats the difference, it looks like it is used the same way…

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  1. Editorial Team
    Editorial Team
    2026-05-15T05:02:14+00:00Added an answer on May 15, 2026 at 5:02 am

    Yeah, it actually does the same thing but for different kind of variables.

    If you have a pointer you have to use ->, while if you have a real value you will use ..

    So for example

    struct mystruct *pointer;
    struct mystruct var;
    
    pointer->field = ...
    var.field = ...
    

    That’s not hard at all. Just remember that with a pointer you will need ->, and . otherwise.

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