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Home/ Questions/Q 8170089
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T21:03:54+00:00 2026-06-06T21:03:54+00:00

Possible Duplicate: What is the most efficient way to clone a JavaScript object? I

  • 0

Possible Duplicate:
What is the most efficient way to clone a JavaScript object?

I have an object like this:

User = {    
  name: "user",
  settings: {
    first: "1",
    second: "2"    
  }    
}

and a second one:

user1 = {
  name: "user1",
  settings: {
    second: "3"
  }
}

now I want to copy user1’s custom values into User, using:

    for(var key in user1){
        User[key] = user1[key];
    }

the result User will be:

User = {
  name: "user1",
  settings: {
    second: "3"
  }
}

User.settings has been entirely replace while I wanted only settings.second to be replaced.

How to achieve this, without knowing how much child object the main object have?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-06T21:03:56+00:00Added an answer on June 6, 2026 at 9:03 pm

    I’ve found that the best way to go is this:

    http://andrewdupont.net/2009/08/28/deep-extending-objects-in-javascript/

    Object.deepExtend = function(destination, source) {
      for (var property in source) {
        if (typeof source[property] === "object" &&
         source[property] !== null ) {
          destination[property] = destination[property] || {};
          arguments.callee(destination[property], source[property]);
        } else {
          destination[property] = source[property];
        }
      }
      return destination;
    };
    
    
    Object.extend(destination, source);
    

    What about this?

        function clone(destination, source) {
            for (var property in source) {
                if (typeof source[property] === "object" && source[property] !== null && destination[property]) { 
                    clone(destination[property], source[property]);
                } else {
                    destination[property] = source[property];
                }
            }
        };
    
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