Question

Possible Duplicate:
What is the !! (not not) operator in JavaScript?
What does the !! operator (double exclamation point) mean in JavaScript?

So I was debuging some code and ran across this:

var foo.bar = 0; // this is actually passed from another function, adding it for context

function(foo) {
    var someVar = !!foo.bar;

    if (foo.bar) {
      // ..stuff happens
    } else {
      // .. something else happens
    }
}

Okay my questions is what is the point of !!? All that is doing is making the 0 === false.

1. Is there any benefit to using that compared to boolean(foo.bar)?

2. foo.bar can be evaluated in an if as is because 0 === false already, so why go through the conversion? (someVar is not reused anywhere else)

Answer 1

This converts a value to a boolean and ensures a boolean type.

"foo"      // Evaluates to "foo".
!"foo"     // Evaluates to false.
!!"foo"    // Evaluates to true.

If foo.bar is passed through, then it may not be 0 but some other falsy value. See the following truth table:

Truth Table for javascript

''        ==   '0'           // false
0         ==   ''            // true
0         ==   '0'           // true
false     ==   'false'       // false
false     ==   '0'           // true
false     ==   undefined     // false
false     ==   null          // false
null      ==   undefined     // true
" \t\r\n" ==   0             // true

Source: Doug Crockford

Javascript also gets really weird when it comes to NaN values. And this is the only case I can think of off the top of my head where !! would behave differently to ===.

NaN   ===  NaN     //false
!!NaN === !!NaN    //true

// !!NaN is false