Question

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Why can't I return a double from two ints being divided

My C++ program is truncating the output of my integer devision even when I try and place the output into a float. How can I prevent this whilst keeping those to variables (a & b) as integers?

user@box:~/c/precision$ cat precision.cpp
#include <iostream>
#include <iomanip>
using namespace std;

int main()
{
  int a = 10, b = 3;
  float ans = (a/b);
  cout<<fixed<<setprecision(3);
  cout << (a/b) << endl;
  cout << ans << endl;
  return 0;
}

user@box:~/c/precision$ g++ -o precision precision.cpp 
user@box:~/c/precision$ ./precision 
3
3.000

Answer 1

Cast the operands to floats:

float ans = (float)a / (float)b;