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Home/ Questions/Q 8611259
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T04:19:52+00:00 2026-06-12T04:19:52+00:00

Possible Duplicate: Why can't variables defined in a conditional be constructed with arguments? Consider

  • 0

Possible Duplicate:
Why can't variables defined in a conditional be constructed with arguments?

Consider this simple example:

/*1*/ int main() {
/*2*/   for (int i(7); i;){break;} 
/*3*/   if (int i(7)) {}
/*4*/ }

Why line-2 compiles just fine, whilst line-3 gives the error? This is little strange to me why if-statement is in this aspect treated worse than for-loop?

If this is compiler specific – I tested with gcc-4.5.1:

prog.cpp: In function ‘int main()’:
prog.cpp:3:7: error: expected primary-expression before ‘int’
prog.cpp:3:7: error: expected ‘)’ before ‘int’

I was inspired by this question

[UPDATE]

I know this compiles just fine:

/*1*/ int main() {
/*2*/   for (int i = 7; i;){break;} 
/*3*/   if (int i = 7) {}
/*4*/ }

[UPDATE2]

It seems to be purely academic question – but this could be extremely important for such types as std::unique_ptr<> which cannot be copied:

#include <memory>
int main() {
  if (std::unique_ptr<int> i = new (std::nothrow) int(7)) {
  }
  if (std::unique_ptr<int> i(new (std::nothrow) int(7))) {
  }
}

Neither of these two kinds are allowed. Not sure about new C++11 syntax {}?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-12T04:19:54+00:00Added an answer on June 12, 2026 at 4:19 am

    The C++ standard doesn’t provide a rationale but I would suspect that using the constructor notation could cause some inconsistencies. For example, since function declarations aren’t allowed in the if statement, the most vexing parse would actually mean what was intended. For example:

    int f();        // function declaration (simple form or the most vexing parse)
    if (int f()) {  // illegal in C++ but, when allowed, would be a zero-initialized int
    }
    

    In C++ 2011 you can use brace-initialization:

    if (int x{f()}) {
        ...
    }
    

    Unfortunately, brace-initialization doesn’t always mean the same thing as using constructor notation (I think it’s called direct-initialization).

    With respect to the update: you can use one of these:

    if (std::unique_ptr<int> p = std::unique_ptr<int>(new int(1))) { ... }
    if (auto p = std::unique_ptr<int>(new int(2))) { ... }
    if (std::unique_ptr<int>{new int(3)}) { ... }
    

    It seems there are plenty of options 🙂

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