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Home/ Questions/Q 6664919
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T02:40:01+00:00 2026-05-26T02:40:01+00:00

Possible Duplicate: Why 'defined() || define()' syntax in defining a constant This piece of

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Possible Duplicate:
Why 'defined() || define()' syntax in defining a constant

This piece of code is created by the zf tool that Zend Framework provides.

defined('APPLICATION_PATH') || define('APPLICATION_PATH', realpath(dirname(__FILE__) . '/../application'));

My questions is :
What is the purpose of this line of code? There are no conditional statements such as if, switch. Does it imply a conditional statement automatically?

Here is how i understand it:
if APPLICATION_PATH is defined, leave it alone else set it to : realpath(dirname(__FILE__) . '/../application').

If my assumption is true this is a really confusing syntax.

Any help will be appreciated.

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  1. Editorial Team
    Editorial Team
    2026-05-26T02:40:02+00:00Added an answer on May 26, 2026 at 2:40 am

    Your assumption is correct. This is just a short hand way of saying

    if (!defined('APPLICATION_PATH')) {
      define('APPLICATION_PATH', '...');
    }
    

    You can easily test this:

    define("foo", "bar");
    defined("foo") || define("foo", "baz");
    var_dump(foo);
    

    Output is bar.

    //define("foo", "bar");
    defined("foo") || define("foo", "baz");
    var_dump(foo);
    

    Output is baz.

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