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Home/ Questions/Q 8954231
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T14:16:29+00:00 2026-06-15T14:16:29+00:00

Possible Duplicate: Why do I get a segmentation fault when writing to a string?

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Possible Duplicate:
Why do I get a segmentation fault when writing to a string?

I have the following program:

#include <iostream>
using namespace std;

void reverseString(char* first, char* last)
{
    while(first < last)
    {
        cout << *first << " " << *last << endl; //for debugging; prints 'H' and 'o' then crashes
        char temp = *last;
        *last = *first; //this line crashes the program
        *first = temp;
        first++;
        last--;
    }
}

int main()
{
    char* s = "Hello";
    reverseString(s, s + strlen(s) - 1);
    cout << s << endl;
}

However, I’m having trouble swapping the values to which the pointers point. I thought *p = *p1 should just set the pointed-to value of p to the pointed-to value of p1, but something seems bugged up. Thanks in advance for any help!

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  1. Editorial Team
    Editorial Team
    2026-06-15T14:16:31+00:00Added an answer on June 15, 2026 at 2:16 pm

    The code looks fine to me. The most likely problem is that the compiler is allowed to assume that string literals are not modified, so it can put them in read-only memory. Try

    char s[] = "Hello";
    

    in main() instead, which creates a writable copy of the string literal.

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