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Home/ Questions/Q 8816023
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T04:31:11+00:00 2026-06-14T04:31:11+00:00

Possible Duplicate: Why do I have to access template base class members through the

  • 0

Possible Duplicate:
Why do I have to access template base class members through the this pointer?

I have a class hierarchy like the following:

template<typename T>
class Base {
protected:
    T t;
};

template<typename T>
class Derived: public Base<T> {
public:
    T get() { return t; }
};

int main() {
    Derived<int> d;
    d.get();
}

The problem is that the protected member variable t is not found in the Base class. Compiler output:

prog.cpp: In member function 'T Derived<T>::get()':
prog.cpp:10:22: error: 't' was not declared in this scope

Is that correct compiler behavior or just a compiler bug? If it is correct, why is it so? What is the best workaround?

Using fully qualified name works, but it seems to be unnecessarily verbose:

T get() { return Base<T>::t; }
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  1. Editorial Team
    Editorial Team
    2026-06-14T04:31:13+00:00Added an answer on June 14, 2026 at 4:31 am

    To use members from template base classes, you have to prefix with this->.

    template<typename T>
    class Derived: public Base<T> {
    public:
        T get() { return this->t; }
    };
    
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