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Possible Duplicate:
Why does Math.Floor(Double) return a value of type Double?
Why does C# Math.Floor() return double instead of int
From the MSDN Docs:
Returns the largest integer less than or equal to the specified double-precision floating-point number
it says it returns an integer. Its ok to return a double, I can always cast it to an int but its just quite strange, isn’t it?
Not really, considering that a
doublecan be a much higher magnitude than anint. You wouldn’t want to overflow an int with the large value that a double could be.Just to show you what I mean:
Double.MaxValue = 1.7976931348623157E+308
Integer.MaxValue = 2,147,483,647
So you could have a double that is 3,000,000,000.50 and floor it, which would overflow the max value of an int.