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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T18:04:59+00:00 2026-06-07T18:04:59+00:00

Possible Duplicate: Why does parseInt(1/0, 19) return 18? I was parsing an integer from

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Possible Duplicate:
Why does parseInt(1/0, 19) return 18?

I was parsing an integer from the result of an expression in javascript.
The expression was (a/b,24), and it is in a method, so I do not have a check on division by zero.
and I am parsing the integer as parseInt(a/b,24)

But I found an unusual thing in it when a=1, b=0 the result was 151176378.

Please explain the reason for this discrepancies.

Appreciate any suggestion.

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  1. Editorial Team
    Editorial Team
    2026-06-07T18:05:00+00:00Added an answer on June 7, 2026 at 6:05 pm

    When you run parseInt(a/b, 24) you are attempting to parse the result of a/b in base 24 (no idea what this number system would look like).

    a/b returns Infinity which is converted to the string value "Infinity" and then parsed using base 24 so you would get the same result with parseInt("Infinity", 24). You would get a result of NaN with any base of 18 or less (i.e. parseInt(1/0, 18)).

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