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Home/ Questions/Q 7666493
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T14:50:47+00:00 2026-05-31T14:50:47+00:00

Possible Duplicate: Why does printf print wrong values? #include<stdio.h> int main(int argc, const char

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Possible Duplicate:
Why does printf print wrong values?

#include<stdio.h>

int main(int argc, const char *argv[]){
    float f1 = 125.2f;

    printf("\n [%f] [%d] [%g]",f1,f1,f1);
    printf("\n [%f] [%g] [%d]",f1,f1,f1);
    printf("\n [%g] [%f] [%d]",f1,f1,f1);
    printf("\n [%g] [%d] [%f]",f1,f1,f1);
    printf("\n [%d] [%g] [%f]",f1,f1,f1);
    printf("\n [%d] [%f] [%g]",f1,f1,f1);  
    getchar();
}  

I can see different output from each printf, though printing the same variable with same format identifier.

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  1. Editorial Team
    Editorial Team
    2026-05-31T14:50:49+00:00Added an answer on May 31, 2026 at 2:50 pm

    printf is not type safe so using a incorrect format descriptor results in Undefined Behavior.

    An Undefined Behavior means that any observable behavior is possible because the code is not abiding the rules laid out by the standard.

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