Question

Possible Duplicate:
Why does this C code work?
How do you use offsetof() on a struct?

I read about this offsetof macro on the Internet, but it doesn’t explain what it is used for.

#define offsetof(a,b) ((int)(&(((a*)(0))->b)))

What is it trying to do and what is the advantage of using it?

Answer 1

It has no advantages and should not be used, since it invokes undefined behavior (and uses the wrong type – int instead of size_t).

The C standard defines an offsetof macro in stddef.h which actually works, for cases where you need the offset of an element in a structure, such as:

#include <stddef.h>

struct foo {
    int a;
    int b;
    char *c;
};

struct struct_desc {
    const char *name;
    int type;
    size_t off;
};

static const struct struct_desc foo_desc[] = {
    { "a", INT, offsetof(struct foo, a) },
    { "b", INT, offsetof(struct foo, b) },
    { "c", CHARPTR, offsetof(struct foo, c) },
};

which would let you programmatically fill the fields of a struct foo by name, e.g. when reading a JSON file.