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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T07:14:38+00:00 2026-05-13T07:14:38+00:00

Possible Duplicate: Why is there not a ForEach extension method on the IEnumerable interface?

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Possible Duplicate:
Why is there not a ForEach extension method on the IEnumerable interface?

First, let me specify I am refering to the List<T> method and not the C# keyword. What would be Microsoft’s reasoning for having the Foreach method on the List<T> collection but no other collection/enumerable type, specifically IEnumerable<T>?

I just discovered this method the other day, and found it to be very nice syntax for replacing traditional foreach loops that only perform one or 2 lines of methods on each object.

It seems like it would be fairly trivial to create an extension method that ,performs this same function. I guess I’m looking at why MS made this decision and based on that if I should just make an extension method.

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  1. Editorial Team
    Editorial Team
    2026-05-13T07:14:39+00:00Added an answer on May 13, 2026 at 7:14 am

    Eric Lippert has responded to this question numerous times, including on his blog.

    His response has been that ForEach() is something you use explicitly for its side effects – whereas LINQ is largely intended to be a side-effect free API to define projections and manipulations on sequences.

    Outside of uses like parallel loops, the functional ForEach syntax doesn’t add much in the way of expressive power, and it is slightly less efficient than a regular foreach loop due to the delegate invocations.

    If you really, really want a ForEach for IEnumerable<T>, it’s not hard to write one:

    public static class ForEachExtension
    {
        public static void ForEach<T>( this IEnumerable<T> seq, Action<T> action )
        {
            foreach( var item in seq ) 
                action( item );
        }
    
        // Here's a lazy, streaming version:
        public static IEnumerable<T> ForEachLazy<T>( this IEnumerable<T> seq, Action<T> action )
        {
            foreach( var item in seq )
            {
                action( item );
                yield return item;
            }
        }
    }
    
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