Question

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Why is this C code causing a segmentation fault?

char* string = "abcd";

now when i try to change some character of this string i get segmentation fault

*string = 'p';

or

string[0] = 'p';
string[0] = 52;

Can someone please explain me the reason that why is it happening.

Thanks

Alok.Kr.

Answer 1

If you write char* string = "abcd"; the string “abcd” is stocked into the static data part of your memory and you can’t modify it.

And if ou write char* string = 'p';, that’s just wrong. First, you try to declare a variable with the same name (string) and, worse, you try to assign a char value to a char pointer variable. This doesn’t work. Same thing : char[0] = 'p'; really means nothing to your compiler except a syntax error.