Question

Possible Duplicate:
Why should the copy constructor accept its parameter by reference in C++?

I have the following code:

class Student {
private:
    int no;
    char name[14];
public:
    void display() const;
    Student(const Student& student); // Line 1
};

I have read that class is a reference type, so why in Line 1 of the above code declared as alias.
Is Line 1 equivalent to: Student(const Student student); ?

Answer 1

I have read that class is a reference type

In C++, the assertion that “class is a reference type” makes no sense. You may have heard this in connection with C# but this is a completely different matter.

Consequently, the whole discussion is moot. To understand the syntax of copy constructors you first need to understand references (those do exist in C++) and classes in general. Grab a good C++ book for beginners.