Question

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why "++x || ++y && ++z" calculate "++x" firstly ? however,Operator "&&" is higher than "||"

The following program does not seem to work as expected. ‘&&’ is to have higher precendence than ‘||’, so the actual output is confusing. Can anyone explain the o/p please?

#include <stdio.h>

int main(int argc, char *argv[])
{
    int x;
    int y;
    int z;

    x = y = z = 1;

    x++ || ++y && z++;

    printf("%d %d %d\n", x, y, z);

    return 0;
}

The actual output is: 2 1 1

TIA.

Answer 1

Precedence and order of evaluation have no relation whatsoever.

&& having higher precedence than || means simply that the expression is interpreted as

x++ || (++y && z++);

Thus, the left-hand operand of || is evaluated first (required because there is a sequence point after it), and since it evaluates nonzero, the right-hand operand (++y && z++) is never evaluated.