Home/ Questions/Q 989949
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Asked: 2026-05-16T05:52:18+00:00

preg_replace(/(/s|^)(php|ajax|c\+\+|javascript|c#)(/s|$)/i, ‘$1#$2$3’, $somevar); It’s meant to turn, for example, PHP into #PHP. Warning: preg_replace():

  • 0
preg_replace("/(/s|^)(php|ajax|c\+\+|javascript|c#)(/s|$)/i", '$1#$2$3', $somevar);

It’s meant to turn, for example, PHP into #PHP.

Warning: preg_replace(): Unknown modifier '|'
Share

Leave an answer

You must login to add an answer.

Need An Account,

1 Answer

  1. Editorial Team

    It’s because you are using the forward slash (/) as your delimiter. When the regex engine gets to /s (3rd character) it thinks the regex is over and the rest of it are modifiers. But no such modifier (|) exists, thus the error.

    Next time, you can either:

    • Change your delimiters to something you won’t use in your regex, ie:

      preg_replace("!(/s|^)(php|ajax|c\+\+|javascript|c#)(/s|$)!i", '$1#$2$3', $somevar);

    • Or escape those characters with a backslash, ie: "/something\/else/"*

    I also suspect you didn’t intend to use /s, but the escape character \s that matches whitespace characters.

    • 0