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Home/ Questions/Q 9219081
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T03:01:13+00:00 2026-06-18T03:01:13+00:00

Pretty new to jquery so this could be a really man type of question.

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Pretty new to jquery so this could be a “really man” type of question. But say I have two functions that I want to combine into one but there are slight differences, for example the next() and the prev() methods and the first and last pseudo-selectors are different in each function:

function rotateImage(){

var currentPhoto = $("#photo_slideshow .current");  
var nextPhoto = currentPhoto.next();

if(nextPhoto.length == 0){
nextPhoto = $("#photo_slideshow div:first");
}

}

function rotateImage2(){

var currentPhoto = $("#photo_slideshow .current");  
var nextPhoto = currentPhoto.prev();

if(nextPhoto.length == 0){
nextPhoto = $("#photo_slideshow div:last");
}
}

There’s got to be a way to combine the two functions to condense the code. Thanks for the help!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-18T03:01:15+00:00Added an answer on June 18, 2026 at 3:01 am

    You need to provide some argument inside function.something that’ll determine whether next is called or previous is called.do something like this.

    function rotateImage(side){
    
    var currentPhoto = $("#photo_slideshow .current");  
    if(side=="next"){
    var nextPhoto = currentPhoto.next();
    if(nextPhoto.length == 0){
    nextPhoto = $("#photo_slideshow div:first");
    }
    if(side=="prev")
    {
    var nextPhoto = currentPhoto.prev();
    if(nextPhoto.length == 0){
    nextPhoto = $("#photo_slideshow div:last");
    }
    }
    

    While calling:
    for next use rotateImage("next") for previous use rotateImage("prev")

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