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Home/ Questions/Q 9200815
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T22:51:05+00:00 2026-06-17T22:51:05+00:00

private SqlCommand createSQLQuery(SqlCommand command) { string[] allTheseWords; if (textBoxAllTheseWords.Text.Length > 0) { allTheseWords =

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private SqlCommand createSQLQuery(SqlCommand command)
{
    string[] allTheseWords;
    if (textBoxAllTheseWords.Text.Length > 0)
    {
        allTheseWords = textBoxAllTheseWords.Text.Split(' ');
        string SQLQuery = "SELECT distinct [skullbase].[dbo].[patients].[name], [skullbase].[dbo].[patients].[dos], [skullbase].[dbo].[patients].[ACC2], [SKULLbase].[dbo].[fullreport].[mrn1], [SKULLbase].[dbo].[fullreport].[ACC], [skullbase].[dbo].[fullreport].[fullreport] FROM [skullbase].[dbo].[fullreport], [skullbase].[dbo].[patients] WHERE ";
        int i = 1;
        foreach (string word in allTheseWords)
        {
            command.Parameters.Add("@word" + i.ToString(), SqlDbType.Text).Value = word;
            SQLQuery = SQLQuery + " [skullbase].[dbo].[fullreport].[fullreport] LIKE @word" + i.ToString() + " AND ";
            i++;
        }
        SQLQuery = SQLQuery + " skullbase.dbo.patients.ACC2 = skullbase.dbo.fullreport.ACC";
        command.CommandText = SQLQuery;
    }
    MessageBox.Show(command.CommandText.ToString());
    return command;
}

The above is my query. The word “word” is not being substituted for the actual value.


allTheseWords = textBoxAllTheseWords.Text.Split(' ');
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  1. Editorial Team
    Editorial Team
    2026-06-17T22:51:06+00:00Added an answer on June 17, 2026 at 10:51 pm

    For starters, when you quote your parameter reference in your SQL CommandText (e.g. …[fullreport] = '@word'…) you are actually just using the literal value '@word'. It is not being interpreted as a parameterized query. To do that you would just use …[fullreport] = @word…)

    Secondly, I do not -think- you can assign multiple parameters with the same parameter name as you are doing in the loop. Each parameter you add should have a unique name.

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