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Home/ Questions/Q 7661121
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T13:33:22+00:00 2026-05-31T13:33:22+00:00

private void button2_Click(object sender, EventArgs e) { SqlConnection con = new SqlConnection(Data Source=SYS12;Initial Catalog=Teju;Integrated

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private void button2_Click(object sender, EventArgs e)
{
    SqlConnection con = new SqlConnection("Data Source=SYS12;Initial Catalog=Teju;Integrated Security=True");
    SqlCommand cmd = new SqlCommand("Select Picture from tblImgData where id= " + listBox1.SelectedValue + " ", con);
    con.Open();
    byte[] byteImg = (byte[])cmd.ExecuteScalar();
    string strfn = Convert.ToString(DateTime.Now.ToFileTime());
    FileStream fs = new FileStream(strfn, FileMode.CreateNew, FileAccess.Write);
    fs.Write(byteImg, 0, byteImg.Length-1);
    fs.Flush();
    fs.Close();
    pictureBox1.Image = Image.FromFile(strfn);
}

This code showing error as “Out of memory.” What might I be doing wrong, or how can I debug and solve this? Thanks!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-31T13:33:23+00:00Added an answer on May 31, 2026 at 1:33 pm

    Use System.Drawing.Image Class to save file then directly assign this image to your picture box.

    Check this:

    private void button2_Click(object sender, EventArgs e)
    {
    
        SqlConnection con = new SqlConnection("Data Source=SYS12;Initial Catalog=Teju;Integrated Security=True");
        SqlCommand cmd = new SqlCommand("Select Picture from tblImgData where id= " + listBox1.SelectedValue + " ", con);
        con.Open();
        byte[] byteImg = (byte[])cmd.ExecuteScalar();
        string strfn = Convert.ToString(DateTime.Now.ToFileTime());
       Stream stream = new MemoryStream(byteImg);
    Image img = System.Drawing.Image.FromStream(stream);
    
    img.Save(strfn , ImageFormat.Jpeg);
        pictureBox1.Image = img;
    }
    
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